TOLONG KERJAKAN ?!?!?!
Jawab:
1 / 1/3 (ab + b)
Penjelasan dengan langkah-langkah:
3log2 = a
2log7 = b
Berdasarkan sifat logaritma,
alogb x blogc = alogc, berarti,
3log2 x 2log7 = ab
3log7 = ab
Lalu,
14log21 = 1 / 21log14, berdasarkan sifat (a^n)log(b^m) = (m/n)alogb, sehingga
14log21 = 1 / (1/3 * 3log14)
14log21 = 1 / (1/3 * (3log7 + 3log2)
14log21 = 1 / (1/3 * (ab + a))
14log21 = 1 / (1/3ab + 1/3a)
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